9v^2=63

Solution for 9v^2=63 equation:

9v^2=63

We move all terms to the left:

9v^2-(63)=0

a = 9; b = 0; c = -63;
Δ = b2-4ac
Δ = 02-4·9·(-63)
Δ = 2268
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2268}=\sqrt{324*7}=\sqrt{324}*\sqrt{7}=18\sqrt{7}$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-18\sqrt{7}}{2*9}=\frac{0-18\sqrt{7}}{18}
=-\frac{18\sqrt{7}}{18}
=-\sqrt{7}
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+18\sqrt{7}}{2*9}=\frac{0+18\sqrt{7}}{18}
=\frac{18\sqrt{7}}{18}
=\sqrt{7}
$